My Math Forum Factor Completely

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 November 13th, 2012, 06:46 PM #1 Senior Member   Joined: Aug 2012 From: South Carolina Posts: 866 Thanks: 0 Factor Completely I have been trying for 2 weeks. Can anyone solve? y = f(x) = X^7 -20X^6 + 177X^5 - 926X^4 +3188X^3. - 7336X^2 +10452X - 6760
 November 13th, 2012, 06:58 PM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,184 Thanks: 481 Math Focus: Calculus/ODEs Re: Factor Completely $x^7-20x^6+177x^5-926x^4+3188x^3-7336x^2+10452x-6760=$ $(x-2)$$x^2-10x+26$$$$x^2-6x+13$$$$x^2-2x+10$$$
 November 13th, 2012, 07:38 PM #3 Senior Member   Joined: Aug 2012 From: South Carolina Posts: 866 Thanks: 0 Re: Factor Completely Wow did u use a computer application Mark? That was quick Also I am supposed to arrive at 7 roots Do those to quadratics factor down to give birth to twins...lol All I know is there is supposed to be 7 factors
 November 13th, 2012, 08:13 PM #4 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,184 Thanks: 481 Math Focus: Calculus/ODEs Re: Factor Completely Yes, each quadratic factor will give two roots, for a total of 7. And I did use the computer to factor.
 November 14th, 2012, 12:07 AM #5 Senior Member   Joined: Aug 2012 From: South Carolina Posts: 866 Thanks: 0 Re: Factor Completely In both classes we r now moving into exponentials, log and ln. Any advice/suggestions?
 November 14th, 2012, 12:09 AM #6 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,184 Thanks: 481 Math Focus: Calculus/ODEs Re: Factor Completely Bone up on your properties of logs, they will come in real handy.
 November 14th, 2012, 12:11 AM #7 Senior Member   Joined: Aug 2012 From: South Carolina Posts: 866 Thanks: 0 Re: Factor Completely Ok
 November 14th, 2012, 12:35 AM #8 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,184 Thanks: 481 Math Focus: Calculus/ODEs Re: Factor Completely For example, suppose after integrating you find: $y=\ln|2x|+C$ yet your textbook gives the answer as: $y=\ln|x|+C$ Many students will ask, "What have I done wrong?"...can you show how the two results are equivalent?
 November 14th, 2012, 12:27 PM #9 Senior Member   Joined: Aug 2012 From: South Carolina Posts: 866 Thanks: 0 Re: Factor Completely let me get back to you on this one. I cannot at this time because have not learned really anything at all about log and ln by late tonight I should be able to answer here
 November 14th, 2012, 12:29 PM #10 Senior Member   Joined: Aug 2012 From: South Carolina Posts: 866 Thanks: 0 Re: Factor Completely Mark I am trying to write down the factors to my org equation but it is cut off and I cannot see the last quadratic could u post again?

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