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November 11th, 2012, 05:04 PM  #1 
Newbie Joined: Nov 2012 Posts: 29 Thanks: 0  Newton's Law (conceptual problem)...
17. Show that Newton's method applied to f(x) in Eq. 6 leads to xsub1 = r + h if xnought = r  h and to xsub1 = rh if xnought = r+h. Interpret the result geometrically. Eq 6 is f(x) = (2x+1)^1/2  (x + 4)^1/2 I know how to do Newton's method. I just don't understand where this talk about the height and radius comes into play. I don't know how to go about solving this problem. Thank you. 
November 11th, 2012, 08:16 PM  #2 
Newbie Joined: Nov 2012 Posts: 29 Thanks: 0  Re: Newton's Law (conceptual problem)...
please.

November 11th, 2012, 08:27 PM  #3 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs  Re: Newton's Law (conceptual problem)...
I just took a look at it, spent some time with it, and do not get the intended result. Are you sure the function is copied correctly?

November 11th, 2012, 09:03 PM  #4 
Newbie Joined: Nov 2012 Posts: 29 Thanks: 0  Re: Newton's Law (conceptual problem)...
i forgot to add. for equation six, a=2 and b=4. it is copied correctly otherwise. 
November 11th, 2012, 09:04 PM  #5 
Newbie Joined: Nov 2012 Posts: 29 Thanks: 0  Re: Newton's Law (conceptual problem)...
that represents that there is a root between 2 and 4.

November 12th, 2012, 07:35 AM  #6 
Newbie Joined: Nov 2012 Posts: 29 Thanks: 0  Re: Newton's Law (conceptual problem)...
nothing?...

November 12th, 2012, 08:47 AM  #7  
Math Team Joined: Sep 2007 Posts: 2,409 Thanks: 6  Re: Newton's Law (conceptual problem)... Quote:
Quote:
Newtons method for solve f(x)= 0 is to construct a sequence of numbers recursively defined by Here and . You have already been told, by MarkFL, that what you are trying to prove is not true.. To see that, let's use specific numbers: r= 2, h= 1. Then [latex]x_0= r h= 1[latex]. and . . That makes which is NOT equal to r+ h= 3.  
November 12th, 2012, 11:01 AM  #8 
Newbie Joined: Nov 2012 Posts: 29 Thanks: 0  Re: Newton's Law (conceptual problem)...
Well, that's the problem. I don't know what else to tell you.


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