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October 26th, 2012, 11:27 AM   #1
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equation of a tangent line

stuck on the last part (part b). so far I got -3(2x_5) +24 as my function. I have 3 as the slope.


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October 28th, 2012, 07:05 PM   #2
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Re: equation of a tangent line

You've done part a very well.

For part b you need to find an equation of a straight line

since you know that the slope of the tangent will be -6 = h'(1)
but the coefficient b has to be found.

This line touches the graph of h at point (1,3),
that is the values agree:
,
in other words


Thus
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October 28th, 2012, 07:52 PM   #3
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Re: equation of a tangent line

Thank you!
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