May 18th, 2008, 03:54 AM  #1 
Newbie Joined: May 2008 Posts: 2 Thanks: 0  Help required PLEASE !!
Thank you for taking the time to read this. I am a simple high school educated chap in sunny Manchester UK who has been given a task as a 'dare'... The task is to find the answer to a Pure Mathematics question, i have no clue as to how these systems work and therefor have resulted in using my common sense and cheek by asking your good selves for assistance. The question is this ' Anyone who can answer: The solution of the equation 8 = 2e 5x is of the form x = ln p q, where p is an integer between 0 and 20 and q is a decimal between 0 and 1. State the values of p and q. Give q as a decimal. p = q = Damn I love equations ' Kind regards John M/cr UK 
May 18th, 2008, 01:57 PM  #2 
Senior Member Joined: Oct 2007 From: Chicago Posts: 1,701 Thanks: 3 
Is that 8= (2e)^(5x), where "^" means "to the power of", or is it 2(e^(5x)) ? and is it ln(p)*q or ln(p*q)? I'm assuming the former in both cases. In the first case: 8 = (2e)^5x = 2^(5x)*e^(5x), 8/(2^5x) = e^5x 8 = 2^3, so 2^(35x) = e^5x Now, take the logarithm (base e that is ln) of both sides, and use the rule that: ln(x^y) = y*ln(x) And I'll let you finish the problem with that. If you need more help, put some effort into it, and show us what you get, and I'll give you some more help... but I can't in good conscience feed you the whole solution. 
May 19th, 2008, 12:46 PM  #3 
Newbie Joined: May 2008 Posts: 2 Thanks: 0 
LOL thanks for your time ha ha.. It started as a joke if i'm truthfull. I know absolutley nothing about MATH except the very basic day to day summing up. All of this is waaaaaay beyond me and I bow to you and your forum friends patience and intelligence in doing them. 

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