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October 5th, 2012, 09:25 PM   #1
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Rolle's Theorem 2

y = f(x) = (x^(2) - 1) / (x) on the closed interval [-1,1]

Can Rolle's Theorem be applied here?


if so apply it now to the open interval (-1,1) such that f ' (c) = 0


Thanks to any and to all for the help. We should have the solution handout in a few days but I can't wait lol

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October 5th, 2012, 10:01 PM   #2
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Re: Rolle's Theorem 2

Is the given function continuous on the given interval?
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October 6th, 2012, 03:15 PM   #3
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Re: Rolle's Theorem 2

Mark,

I graphed it and see it is not continuous. It has quite a jump. Algebraically, I am getting x = root -1 and x = root 1

throw out root -1 and root 1 is just 1. 1 is an endpoint so I beleive u said we throw out

so I have learned from visual inspection of the graph it is not continuous on the closed interval. so right there I believe I can throw out but algebraically I verified that there is no point c between a and b on closed interval so we end right here.

correct?
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October 6th, 2012, 07:22 PM   #4
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Re: Rolle's Theorem 2

Once you determine the function is not continuous on the given interval, then Rolle's theorem cannot be applied.
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October 6th, 2012, 07:35 PM   #5
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Re: Rolle's Theorem 2

Ok
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