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 September 22nd, 2012, 11:37 AM #1 Senior Member   Joined: Aug 2012 From: South Carolina Posts: 866 Thanks: 0 Is this Trick Question?? Let f(x) = { x^2 +2, x<2 4-Cx, x>=2 Assuming that f is continuous at x = 2, what MUST be the value of C ? Is the answer here 1 ? or 1 or 0 ? how to write properly ?
 September 22nd, 2012, 11:42 AM #2 Math Team   Joined: Sep 2007 Posts: 2,409 Thanks: 6 Re: Is this Trick Question?? No, that is NOT a trick question- it is, in fact, a fairly basic question about the definition of "continuous". What is $\lim_{x\to 2^-} f(x)$? What is $\lim_{x\to 2^+} f(x)$? What does the fact that f is continuous at 2 tell you about those limits?

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