September 22nd, 2012, 11:37 AM  #1 
Senior Member Joined: Aug 2012 From: South Carolina Posts: 866 Thanks: 0  Is this Trick Question??
Let f(x) = { x^2 +2, x<2 4Cx, x>=2 Assuming that f is continuous at x = 2, what MUST be the value of C ? Is the answer here 1 ? or 1 or 0 ? how to write properly ? 
September 22nd, 2012, 11:42 AM  #2 
Math Team Joined: Sep 2007 Posts: 2,409 Thanks: 6  Re: Is this Trick Question??
No, that is NOT a trick question it is, in fact, a fairly basic question about the definition of "continuous". What is ? What is ? What does the fact that f is continuous at 2 tell you about those limits? 

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