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September 4th, 2012, 03:39 AM   #1
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Vectors in three dimensional space

Point A is on the straight line x=(-1,-1,0)+t(2,-3,5)
Point B is on the straight line x=(-1,6,-9)+s(1,-2,4)
Point C(2,-3,6) is the middle of the vector AB.
Find points A and B.


Edit: in 2 dimensional space, if point B(Xb,Yb) is in the middle of the line AC A(Xa,Ya) C(Xc,Yc) then Xb=(Xa+Xc)/2 and Yb=(Ya+Yc)/2. Does that formula work in three dimensional space aswell?
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September 4th, 2012, 07:07 AM   #2
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Re: Vectors in three dimensional space

http://en.wikipedia.org/wiki/Midpoint#Formulas
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September 4th, 2012, 12:23 PM   #3
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Re: Vectors in three dimensional space

Thank you greg, that was helpful.
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