 My Math Forum subsitution to find the following indefinite integrals

 Calculus Calculus Math Forum

 April 14th, 2008, 10:40 AM #1 Newbie   Joined: Mar 2008 Posts: 6 Thanks: 0 subsitution to find the following indefinite integrals x^2+2 / x^3 + 6x + 3 I got: u = x^3 + 6x + 3 and du = 3x^2 + 6 (1/2) so du actually = (1/2)du so then you get: (1/2)du / u... but in the rules it's only plain du/u or u^-1 du... so what should i do? multiply both by 2... then the u would be different... what's my next step? April 14th, 2008, 11:51 AM #2 Global Moderator   Joined: Nov 2006 From: UTC -5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms Integral(k * blah(u) du) = k * Integral (blah(u) du) Tags find, indefinite, integrals, subsitution Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post tsl182forever8 Calculus 1 March 15th, 2012 04:33 PM BinaryWriter Calculus 4 March 10th, 2012 11:32 PM BinaryReader Calculus 4 March 1st, 2012 01:41 AM Heras Calculus 2 February 13th, 2012 12:19 PM Heras Real Analysis 0 December 31st, 1969 04:00 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top      