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April 14th, 2008, 10:40 AM   #1
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subsitution to find the following indefinite integrals

x^2+2 / x^3 + 6x + 3

I got:
u = x^3 + 6x + 3
and du = 3x^2 + 6 (1/2)
so du actually = (1/2)du

so then you get: (1/2)du / u... but in the rules it's only plain du/u or u^-1 du... so what should i do? multiply both by 2... then the u would be different... what's my next step?
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April 14th, 2008, 11:51 AM   #2
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Integral(k * blah(u) du) = k * Integral (blah(u) du)
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