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April 14th, 2008, 10:40 AM  #1 
Newbie Joined: Mar 2008 Posts: 6 Thanks: 0  subsitution to find the following indefinite integrals
x^2+2 / x^3 + 6x + 3 I got: u = x^3 + 6x + 3 and du = 3x^2 + 6 (1/2) so du actually = (1/2)du so then you get: (1/2)du / u... but in the rules it's only plain du/u or u^1 du... so what should i do? multiply both by 2... then the u would be different... what's my next step? 
April 14th, 2008, 11:51 AM  #2 
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms 
Integral(k * blah(u) du) = k * Integral (blah(u) du)


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