My Math Forum Area Bounded By The Curve

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 June 13th, 2012, 01:07 PM #1 Newbie   Joined: Feb 2012 Posts: 8 Thanks: 0 Area Bounded By The Curve Hello, can somebody help me please? I have the following question...... Find the area bounded by the curve y=1/x between x=2 and x=6. (to 3dp) I have 6 ? 1/x dx 2 6 =[ln |x|] 2 =ln6-ln2 am I going along the correct path? if so, I have reached a point where I cant see how to progress. could somebody advise me please?
June 13th, 2012, 02:01 PM   #2
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Re: Area Bounded By The Curve

Hello, Trafford99!

Quote:
 $\text{Find the area bounded by the curve }\,y\,=\,\frac{1}{x}\:\text{ between }x=2\text{ and }x=6\;\text{ (to 3dp)}$ $\text{I have: }\:\int^6_2 \frac{dx}{x} \;=\;\ln|x|\,\bigg]^6_2 \;=\;\ln\,\!6\,-\,\ln\,\!2$ $\text{I have reached a point where I can't see how to proceed.}$

$\text{You can now enter this into your calculator: }\:\fbox{\text{ln}}\;\fbox{6}\; \fbox{^{\_}}\;\fbox{\text{ln}}\;\fbox{2}\;\fbox{=}$

$\text{Or note that: }\:\ln\,\!6\,-\,\ln\,\!2 \:=\:\ln\,\!3\,\,\text{ and enter: }\:\fbox{\text{\ln}}\;\fbox{3}$

 June 14th, 2012, 10:42 AM #3 Newbie   Joined: Feb 2012 Posts: 8 Thanks: 0 Re: Area Bounded By The Curve Is that it? I thought there was parts that I had missed as I struggle with Integration. Thank you very much. You have cheered an old man up.

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