March 27th, 2008, 06:36 PM  #1 
Newbie Joined: Mar 2008 Posts: 1 Thanks: 0  Integration of Gaussian Surface
Hello, first time posting here. We all know the nice way to integrate y = exp(ar^2) using polar coordinates, right? What about y = exp(r^2/(2*(a+bsin(n*theta  phi))^2) Obviously I am trying to make the denominator in the exponential argument look similar to the standard deviation (sigma) of the standard Gaussian y = exp(r^2/(2*sigma^2)). Perhaps I should write the sinusoid term in the numerator (similar to the ar^2)? If anyone knows how to get the normalization factor for this form of Gaussian, that'd be great to see! Cheers 
March 28th, 2008, 05:46 PM  #2  
Global Moderator Joined: May 2007 Posts: 6,377 Thanks: 541  Re: Integration of Gaussian Surface Quote:
 

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