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April 12th, 2012, 09:23 AM   #1
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surface Integration

need to calculate surface between fx and gx. not sure i used correct word surface.


fx=gx im stock, hope someone can show me how to do it.
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April 12th, 2012, 11:02 AM   #2
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Re: surface Integration

While surface isn't an incorrect term, typically the word area is used.

For finding the intersections, write the equation as:















We may determine that on (-1,1) using a test point (x = 0) that we have and so the area A bounded by the two functions is:

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April 12th, 2012, 11:45 AM   #3
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Re: surface Integration

is possible to use long division methode? if yes how, because teacher say is possible to use long division, but i dont see fx degree is higher then gx and this problem is not in form
can you do one step more, dont understand this one.
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April 12th, 2012, 11:51 AM   #4
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Re: surface Integration

I wouldn't use division, just factoring because it's simpler in this case.

We have:





The two terms on the left have a common factor of so we have:





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April 12th, 2012, 12:01 PM   #5
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Re: surface Integration

can you tell me how to use division in this case. i know how to use division methode but dont know division by what? i still missing something...
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April 12th, 2012, 12:16 PM   #6
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Re: surface Integration

Well, we could state:



So we may state:



So now, when we equate the two functions to find the intersections, we have:















Now you see why I recommend just factoring, it is simpler.
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April 12th, 2012, 02:05 PM   #7
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Re: surface Integration

aaaaaaa now i see, thanks alot but dont know why im very bad in calculate area ....
like this 2 problems.
a) y=fx=
lines are x=0 and x=2

b) y=fx
so this one


so

i miss gx?
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April 13th, 2012, 02:58 AM   #8
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Re: surface Integration

not sure im doing right, hope someone can help me out. thanks!
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April 13th, 2012, 03:12 AM   #9
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Re: surface Integration

2
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April 13th, 2012, 04:28 AM   #10
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Re: surface Integration

confused
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