User Name Remember Me? Password

 Calculus Calculus Math Forum

 March 20th, 2012, 10:47 PM #1 Member   Joined: Feb 2012 Posts: 44 Thanks: 0 2nd, 3rd and 4th derivatives My attempt at calculating these: a) d^2/(dx^2): ln(x+1) b) d^3/(dx^3): x^7 + 4x^6 - x^2 c) d^2/(dx^2): 1/(x + 1) d) d^4/(dx^4): cos(2x) a) Product rule: 1/x(x + 1) + ln(1)= 1 + 1/x + ln Linearity rule: -(1/x^2) + 1/x b) Linearity rule: 7x^6 + 6x^4 - 2x= 6(7x)^5 + 4(6x)^3 - 2= (5)(6)(7x)^4 + (3)(4)(6x)^2 = 210x^4 + 72x^2 c) Quotient rule: ((0)(x + 1) - (1)(1))/(x + 1)^2= -1/(x + 1)^2= ((0)(x+1)^2 - (-1)2(x + 1))/[(x + 1)^2]^2= (-2x - 2)/(x + 1)^4 d) the answer ends up being: cos(2x) + sin(2) I think Do these look valid? March 20th, 2012, 11:13 PM #2 Senior Member   Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: 2nd, 3rd and 4th derivatives a) b) c) d) Tags 2nd, 3rd, 4th, derivatives Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post johngalt47 Calculus 2 November 23rd, 2013 11:44 AM fantom2012 Calculus 3 May 6th, 2012 07:53 PM Arley Calculus 5 April 13th, 2012 06:56 PM r-soy Calculus 2 November 27th, 2010 08:26 AM Calavan11 Calculus 2 December 11th, 2009 04:42 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top       