My Math Forum (Torus/Volume)

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 November 3rd, 2015, 12:18 AM #1 Newbie   Joined: Nov 2015 From: canada Posts: 3 Thanks: 0 (Torus/Volume) Hello. I'm really new to this place and hope I can get some help with these two questions.Thank you so much in advance. 1) We are emptying a spherical tank (not completely full) into a tank which is shaped like a torus. What percentage of the torus is filled? Refer to the figure below. Second question: A mine shaft can be approximated by the solid of revolution below. The shaft is filled with water. a) How long would it take to empty the shaft if we are using a ramp that pumps 2500 U.S gallons per hour? b) If the water in the shaft is pumped into a truck with the shape described below, what is the minimum number of trucks required? Last edited by skipjack; November 5th, 2015 at 02:53 AM.
 November 4th, 2015, 03:49 PM #2 Math Team   Joined: Jul 2011 From: Texas Posts: 2,805 Thanks: 1449 volume of water in the spherical tank ... $\displaystyle V = \pi \int_{-3}^2 (9 - y^2) \, dy$ volume of the torus (using a theorem of Pappus) ... V = (cross sectional area)(circumference of centroid rotation) = $\pi \cdot (2\pi \cdot 7)$ mine shaft volume (in $m^3$ which will have to be converted to gals) ... $\displaystyle V = \frac{1250 \pi^2}{11} \int_{50/11}^{100} \left(\frac{100}{y}+3\right) \, dy$ single truck volume ... $\displaystyle V = \pi \int_2^4 9^2 - \bigg[(x-3)^4+7\bigg]^2 \, dx$ Thanks from Benit13
 November 5th, 2015, 01:17 AM #3 Newbie   Joined: Nov 2015 From: canada Posts: 3 Thanks: 0 Many Thanks. I got them I guess. Last edited by skipjack; November 5th, 2015 at 02:53 AM.
 November 5th, 2015, 01:19 AM #4 Newbie   Joined: Nov 2015 From: canada Posts: 3 Thanks: 0 Thank you very much
 November 5th, 2015, 08:51 AM #5 Math Team   Joined: Jul 2011 From: Texas Posts: 2,805 Thanks: 1449 Mistake in the mine-shaft volume ... forgot my addition sign and multiplied the constants in front of the integral instead of adding them. should be $\displaystyle V = \frac{1250\pi}{11}+ \pi \int_{50/11}^{100} \left(\frac{100}{y}+3 \right) \, dy$ mea culpa ... it happens.

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