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 February 19th, 2012, 10:10 PM #1 Senior Member   Joined: Jan 2009 Posts: 344 Thanks: 3 Stuck on this problem. $\huge \text{ \frac{dy}{dx}=\frac{e^{(x+y)}}{y-1}}$
 February 19th, 2012, 10:21 PM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs Re: Stuck on this problem. We are given: $\frac{dy}{dx}=\frac{e^{x+y}}{y-1}$ Separate variables: $(y-1)e^{-y}\,dy=e^{x}\,dx$ Integrate: $\int ye^{-y}-e^{-y}\,dy=\int e^{x}\,dx$ The solution y is implicitly given by $-ye^{-y}=e^x+C$

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