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 February 14th, 2012, 10:16 AM #1 Newbie   Joined: Jan 2012 Posts: 29 Thanks: 0 solving a limit involving tangent How do I solve this equation? lim x>0 (x^3 - 2x^2 + x)/tanx
 February 14th, 2012, 11:14 AM #2 Senior Member   Joined: Jul 2011 Posts: 227 Thanks: 0 Re: solving a limit involving tangent $\lim_{x \to 0} \frac{x^3-2x^2+x}{\tan(x)}$ With l'Hopital's rule: $=\lim_{x \to 0} \frac{3x^2-4x+1}{\frac{1}{\cos^2(x)}}=1$ It's not an equation you have to solve, but a limit you have to compute.
 February 14th, 2012, 11:24 AM #3 Newbie   Joined: Jan 2012 Posts: 29 Thanks: 0 Re: solving a limit involving tangent How do I do it without Hopital's rule?

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