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October 20th, 2015, 06:04 PM   #1
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How to find the tangent line?

At what point on the curve y = square root 1 + 2x is the tangent line perpendicular to the line 6x + 2y = 1?
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October 20th, 2015, 07:04 PM   #2
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Determine the slope of the line 6x+2y=1

Slope of a line perpendicular to 6x+2y=1 is the opposite reciprocal of the line's slope.

Set the derivative of the curve equal to the opposite reciprocal value and solve for x ... then sub the value found for x into the curve's equation to determine the y-coordinate.
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