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December 30th, 2011, 01:44 AM  #1 
Member Joined: Aug 2011 Posts: 78 Thanks: 0  The value of g in the gradient formula
Hello, But of a dull question really but it does not care to explain in the book I have, the value of g in this formula: if y=f(x)± g(x) then dy/dx=f'(x)±g'(x) thanks 
December 30th, 2011, 01:52 AM  #2 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond  Re: The value of g in the gradient formula
The derivative of the sum is the sum of the derivatives. g is a function of x. Example: y = 2x² + x³, f(x) = 2x², f'(x) = 4x, g(x) = x³, g'(x) = 3x², dy/dx = 4x + 3x². 
December 30th, 2011, 02:00 AM  #3  
Member Joined: Aug 2011 Posts: 78 Thanks: 0  Re: The value of g in the gradient formula Quote:
 
December 30th, 2011, 02:01 AM  #4  
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs  Re: The value of g in the gradient formula
From another forum: Quote:
 
December 30th, 2011, 02:14 AM  #5  
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond  Re: The value of g in the gradient formula Quote:
It may be a constant function, in which case it will be the same value regardless of the value of x; e.g: g(x) = 3, g'(x) = 0. It may be a rational function, e.g: g(x) = (x² + 2)/(x³  1), which is undefined for x = 1. etc.  
December 30th, 2011, 03:21 AM  #6 
Member Joined: Aug 2011 Posts: 78 Thanks: 0  Re: The value of g in the gradient formula
thanks again I love this forum people are so helpful!


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