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October 18th, 2015, 05:08 AM   #1
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Discrete and combinational math

∃x∀y(x != 0 for all real numbers, is it true or false

Last edited by xsoreal; October 18th, 2015 at 05:49 AM.
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October 18th, 2015, 01:01 PM   #2
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Quote:
Originally Posted by xsoreal View Post
∃x∀y(x != 0 for all real numbers, is it true or false
Statement part after y is screwed up.
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October 19th, 2015, 04:26 AM   #3
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That makes no sense. It say "there exist x such that, for all y, x is not equal to 0". The conclusion makes no reference to "y". Without the "y", of course, there exist a number that is not equal to 0!
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