October 18th, 2015, 05:08 AM  #1 
Newbie Joined: Oct 2015 From: antalya Posts: 1 Thanks: 0  Discrete and combinational math
∃x∀y(x != 0 for all real numbers, is it true or false
Last edited by xsoreal; October 18th, 2015 at 05:49 AM. 
October 18th, 2015, 01:01 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,730 Thanks: 689  
October 19th, 2015, 04:26 AM  #3 
Math Team Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 
That makes no sense. It say "there exist x such that, for all y, x is not equal to 0". The conclusion makes no reference to "y". Without the "y", of course, there exist a number that is not equal to 0!


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