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December 8th, 2011, 10:05 AM   #1
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difficult question

Can any one solve Q number 8 ??
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December 8th, 2011, 02:29 PM   #2
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Re: difficult question

Looks like 3. The 2 break points for the function change and 0 for |x|.
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December 8th, 2011, 06:07 PM   #3
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Re: difficult question

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Originally Posted by mathman
...and 0 for |x|.
While the function(s) are not differentiable at x = 0, aren't they still continuous?
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December 9th, 2011, 01:44 PM   #4
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Re: difficult question

You're right. I misread the problem. I was thinking of the derivative.
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