January 17th, 2008, 10:08 PM  #1 
Newbie Joined: Jan 2008 Posts: 1 Thanks: 0  linearization
I am approximating functions using taylor series, but I am confused on how to derive it. So say I can use a degree 1 function p(x) to approximate ln(x) at 1. I want p(1) = ln(1) p'(1) = ln'(1) I can get a line by definition of slope p(x) = 0 + (x1) But for degree 2 it gets complicated for me. p(1) = ln(1) p'(1) = ln'(1) p''(1) = ln''(1) Now I know the formula is p(x) = 0 + (x1) + 1/2(x1)^2 but I am not sure how to derive it besides the power series. I want to think about it in terms of all the derivatives at a point equaling the derivatives of the function. So I set up this system a + b(1) + c(1)^2 = p(1) (1) + 2c(1) = p'(1) 2 = p''(1) But this doesn't seem to be working. How can I derive the formula for taylor series without thinking of power series, because I am kind of confused on where the (xa)^n/n! exactly comes from. Thank you very much! 
January 18th, 2008, 06:12 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 16,792 Thanks: 1238 
You wrote (1) + 2c(1) = p'(1); did you mean b + 2c(1) = p'(1)?


Tags 
linearization 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
linearization  nicoleb  Calculus  13  November 23rd, 2012 01:11 PM 
Linearization problem  rgarcia128  Calculus  2  October 17th, 2011 06:49 AM 
Linearization Help  Nimmy101  Calculus  1  September 27th, 2011 01:47 AM 
Linearization :( HELP!  it's a secret!  Calculus  1  March 9th, 2011 09:15 PM 
Linearization  JordanReich  Calculus  2  October 30th, 2010 11:37 AM 