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January 15th, 2008, 04:24 PM   #1
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Area Between Curves Problem

Could someone help me with this problem?

y=sin2x
y=cosx
x=0
x=pi/2

I need to find the area enclosed by these lines and curves

So far I have...

A=integral from 0 to pi/2 of [(sin2x)-(cosx)]dx

Hopefully I'm right about that. But then, I have a hard time doing the anti-derivatives of trig functions and that's where I'm confused. Thanks.[/code]
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January 18th, 2008, 03:30 AM   #2
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An antiderivative is -cos(2x)/2 - sin(x).
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January 18th, 2008, 07:23 AM   #3
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Can you take the derivative of sin and cos? The antiderivative is... well... the opposite.
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