January 15th, 2008, 04:24 PM  #1 
Newbie Joined: Sep 2007 Posts: 14 Thanks: 0  Area Between Curves Problem
Could someone help me with this problem? y=sin2x y=cosx x=0 x=pi/2 I need to find the area enclosed by these lines and curves So far I have... A=integral from 0 to pi/2 of [(sin2x)(cosx)]dx Hopefully I'm right about that. But then, I have a hard time doing the antiderivatives of trig functions and that's where I'm confused. Thanks.[/code] 
January 18th, 2008, 03:30 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 19,059 Thanks: 1619 
An antiderivative is cos(2x)/2  sin(x).

January 18th, 2008, 07:23 AM  #3 
Senior Member Joined: Oct 2007 From: Chicago Posts: 1,701 Thanks: 3 
Can you take the derivative of sin and cos? The antiderivative is... well... the opposite.


Tags 
area, curves, problem 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
area under curves  alexmath  Calculus  1  April 13th, 2013 05:34 AM 
Area between two curves  chrishaig  Calculus  2  June 28th, 2012 02:21 PM 
area between curves.  FreaKariDunk  Calculus  3  September 11th, 2011 04:39 PM 
help...area between curves  izseekzu  Calculus  4  January 25th, 2010 07:15 AM 
Area between 2 curves problem  biowolf89  Calculus  2  February 5th, 2008 05:29 AM 