January 15th, 2008, 05:24 PM  #1 
Newbie Joined: Sep 2007 Posts: 14 Thanks: 0  Area Between Curves Problem
Could someone help me with this problem? y=sin2x y=cosx x=0 x=pi/2 I need to find the area enclosed by these lines and curves So far I have... A=integral from 0 to pi/2 of [(sin2x)(cosx)]dx Hopefully I'm right about that. But then, I have a hard time doing the antiderivatives of trig functions and that's where I'm confused. Thanks.[/code] 
January 18th, 2008, 04:30 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 18,594 Thanks: 1492 
An antiderivative is cos(2x)/2  sin(x).

January 18th, 2008, 08:23 AM  #3 
Senior Member Joined: Oct 2007 From: Chicago Posts: 1,701 Thanks: 3 
Can you take the derivative of sin and cos? The antiderivative is... well... the opposite.


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