My Math Forum Area Between Curves Problem

 Calculus Calculus Math Forum

 January 15th, 2008, 04:24 PM #1 Newbie   Joined: Sep 2007 Posts: 14 Thanks: 0 Area Between Curves Problem Could someone help me with this problem? y=sin2x y=cosx x=0 x=pi/2 I need to find the area enclosed by these lines and curves So far I have... A=integral from 0 to pi/2 of [(sin2x)-(cosx)]dx Hopefully I'm right about that. But then, I have a hard time doing the anti-derivatives of trig functions and that's where I'm confused. Thanks.[/code]
 January 18th, 2008, 03:30 AM #2 Global Moderator   Joined: Dec 2006 Posts: 19,059 Thanks: 1619 An antiderivative is -cos(2x)/2 - sin(x).
 January 18th, 2008, 07:23 AM #3 Senior Member   Joined: Oct 2007 From: Chicago Posts: 1,701 Thanks: 3 Can you take the derivative of sin and cos? The antiderivative is... well... the opposite.

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