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August 30th, 2011, 06:38 PM   #1
 
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Find k such that the line is tangent to the function.

I am having extreme trouble with this differentiation problem. It says, "Find k such that the line is tangent to the graph of the function."

Function
F(x) = x^2 - kx

Line
y = 4x - 9

I don't understand the step where you set f(x) to equal y. How do you get rid of the k?
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August 30th, 2011, 08:30 PM   #2
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Re: Fine k such that the line is tangent to the function.

so the slope of the line and the function are the same (one condition of tangency).

so the line and curve intersect (other condition of tangency).







so k = 2, -10.
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August 31st, 2011, 04:16 AM   #3
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Re: Fine k such that the line is tangent to the function.

Fermat, prior to Newton and Leibniz, had a method for problems like this. It uses the fact that a tangent line has a "second order" intersection with a curve. That is, if f(x) is tangent to t(x) at , must be a double root of f(x)= g(x). Your given curve is and your desired tangent line is so we look at the equation which is the same as .

By the quadratic formula, solutions are given by . There will be a double root if and only if the discriminant, . Solve that equation for two values of k.
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