December 9th, 2007, 07:34 AM  #1 
Newbie Joined: Dec 2007 Posts: 2 Thanks: 0  Integral problem
Integrate on both sides: dy = 1/(c*x^2 + 2*b*c*x) * dx b and c are constants c is positive 
December 25th, 2009, 10:54 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 19,547 Thanks: 1752 
Use partial fractions.

December 25th, 2009, 02:52 PM  #3 
Senior Member Joined: Dec 2009 From: Las Vegas Posts: 209 Thanks: 0  Re: Integral problem
Hi Polybius; Yes, partial fractions is the way to go, but it doesn't look easy. 
December 25th, 2009, 04:02 PM  #4  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 407  Re: Integral problem Quote:  
December 25th, 2009, 06:42 PM  #5 
Senior Member Joined: Feb 2009 From: Adelaide, Australia Posts: 1,519 Thanks: 3  Re: Integral problem
Partial fractions method gives which leads to the same result

December 26th, 2009, 05:32 AM  #6 
Global Moderator Joined: Dec 2006 Posts: 19,547 Thanks: 1752 
Not quite. If b is nonzero, which is subtly different from soroban's result. If b = 0, the answer is 1/(cx) + C. 

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