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September 27th, 2015, 05:53 PM   #1
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Math Focus: Certainty
Riemann sum limit.

I want to evaluate $\displaystyle \lim_{n \to \infty}$ for the following equation.

$\displaystyle \frac{10e^{-5n-5}}{n}$

I wish to do so in order to calculate the definite integral.

As $\displaystyle n \to \infty$, the numerator approaches 0 and the denominator approaches infinity. Therefore the limit is 0?

This can't be correct as the definite integral I calculated was close to 1.

Would I have to evaluate using partial sums??

Thank you in advance.

Last edited by hyperbola; September 27th, 2015 at 05:57 PM.
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September 27th, 2015, 06:20 PM   #2
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That limit is 0.

What is the integral you are trying to solve?
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September 28th, 2015, 01:14 PM   #3
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Is $\displaystyle \frac{10e^{-5n- 5}}{n}$ the value at the nth point or the sum of the values of n terms?

Last edited by greg1313; September 28th, 2015 at 01:29 PM.
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