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 September 23rd, 2015, 07:43 AM #1 Member     Joined: Nov 2014 From: SG Posts: 55 Thanks: 1 Simple question Given that k = ln 50/60 and A = 10/60 The given equation is A = e^(kt) 1) 10/60 = e^(kt) ln 10/60 = kt t = (ln 10/60 ) / ln (50/60) = 9.827 2) 10/60 = e^ (ln (50/60)t) 10/60 = 50/60 t t = 0.2 Why do I get 2 different answers? Did I do anything wrong? Last edited by skipjack; September 23rd, 2015 at 07:09 PM.
September 23rd, 2015, 07:54 AM   #2
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Quote:
 Originally Posted by KaiL Given that k = ln 50/60 and A = 10/60 The given equation is A = e^(kt) 1) 10/60 = e^(kt) ln 10/60 = kt t = (ln 10/60 ) / ln (50/60) = 9.827 2) 10/60 = e^ (ln (50/60)t) 10/60 = 50/60 t t = 0.2 Why do I get 2 different answers? Did I do anything wrong?
Your second answer is wrong because you treated it as ln((50/60)t) rather than ln(50/60) times t.

Last edited by skipjack; September 23rd, 2015 at 07:10 PM.

September 23rd, 2015, 08:03 AM   #3
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Quote:
 Originally Posted by Country Boy Your second answer is wrong because you treated it as ln((50/60)t) rather than ln(50/60) times t.
Oh I see. Thanks for correcting my mistake.

Last edited by skipjack; September 23rd, 2015 at 07:10 PM.

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