My Math Forum Piecewise constant function on my Ti-84

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 April 6th, 2011, 04:38 AM #1 Newbie   Joined: Apr 2011 Posts: 2 Thanks: 0 Piecewise constant function on my Ti-84 Today in class, we've talked about limits and the continuity of functions and this was an example: f(x)={ |x-1| if x<2 1-x+1/2 x² if 2?x?4 26/(5x-15) if x>4 This is a piecewise constant function, but how can I put this is my Ti-84 if I want to see a graph of it?
 April 6th, 2011, 05:28 AM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,968 Thanks: 1152 Math Focus: Elementary mathematics and beyond Re: Piecewise constant function on my Ti-84 Y=abs(x-2)(x<2)+(1-x+x^2/2)(2?x?4)+(26/(5x-15))(x>4) The comparison operators are in 2ND-MATH. The abs() (absolute value) function is the first entry in the catalog in 2ND-0.
 April 6th, 2011, 10:21 AM #3 Senior Member   Joined: Apr 2007 Posts: 2,140 Thanks: 0 Texas Instruments make great calculators.
April 6th, 2011, 11:09 AM   #4
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Re: Piecewise constant function on my Ti-84

Quote:
 Originally Posted by greg1313 Y=abs(x-2)(x<2)+(1-x+x^2/2)(2?x?4)+(26/(5x-15))(x>4) The comparison operators are in 2ND-MATH. The abs() (absolute value) function is the first entry in the catalog in 2ND-0.
Thank you
but when I put them all together in "Y1=....", with the "+" between them, I became a completely different graph than it was supposed to be
that's OK now, because I've put them all apart into functions (Y1=abs(x-1)(x<2), Y2=(1-x+x²/2)... )
Y1 and Y3 are fine, but the Y2 gives me the complete parabola and not the one for 2?x?4

 April 6th, 2011, 12:06 PM #5 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,968 Thanks: 1152 Math Focus: Elementary mathematics and beyond Re: Piecewise constant function on my Ti-84 I made a mistake. Here's the correction, which displays a correct graph: Y=(abs(x-1))(x<2)+(1-x+x^2/2)(2?x)(x?4)+(26/(5x-15))(x>4)

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