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 April 2nd, 2011, 05:16 PM #1 Member   Joined: Apr 2011 Posts: 46 Thanks: 0 Evaluate by direct integration anyone able to help me with question 7 part a on this paper?
April 2nd, 2011, 05:22 PM   #2
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Re: Evaluate by direct integration

[attachment=0:3lh0t7yp]practice-exam-2010-MA1003.pdf[/attachment:3lh0t7yp]here it is attached pdf format quuestion 7 a
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 practice-exam-2010-MA1003.pdf (133.0 KB, 25 views)

 April 2nd, 2011, 05:28 PM #3 Senior Member   Joined: Apr 2007 Posts: 2,140 Thanks: 0 Google LaTeX AoPS.
 April 2nd, 2011, 05:37 PM #4 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Evaluate by direct integration You are given: $\int_0\,^2$$10x^3-5x^4$$\,dx$ Using the power rule $\int x^n\,dx=\frac{x^{n+1}}{n+1}+C,n\ne-1$ and the anti-derivative form of the fundamental theorem of calculus, we have: $\int_0\,^2$$10x^3-5x^4$$\,dx=5\int_0\,^2$$2x^3-x^4$$\,dx=5$\frac{2x^4}{4}-\frac{x^5}{5}$_0^2=\frac{1}{2}$x^4$$5-2x$$$_0^2=\frac{1}{2}$$16(5-4)$$=8$
 April 2nd, 2011, 05:56 PM #5 Member   Joined: Apr 2011 Posts: 46 Thanks: 0 Re: Evaluate by direct integration thanks i think i understand it now

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