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September 18th, 2015, 08:39 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,746 Thanks: 2133 
Below is the first. The second can be done in a similar fashion. $\displaystyle f(x) = \begin{cases}2  3x^2/4 & \text{if } 2 \leqslant x < 1 \\ 3 & \text{if } \ x = 1 \\ 2  3x^2/4 & \text{if } 1 \leqslant x < 2 \\ 3x^2/4 + 6x  10 & \text{if } \ 2 < x \leqslant 4\end{cases}$ 
September 19th, 2015, 06:39 AM  #3 
Math Team Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 
skipjack is assuming that the curved portions are parabolas. That cannot be determined from the graphs.

September 19th, 2015, 08:22 AM  #4 
Math Team Joined: Jul 2011 From: Texas Posts: 2,943 Thanks: 1547  

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