
Calculus Calculus Math Forum 
 LinkBack  Thread Tools  Display Modes 
September 18th, 2015, 08:39 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,966 Thanks: 2216 
Below is the first. The second can be done in a similar fashion. $\displaystyle f(x) = \begin{cases}2  3x^2/4 & \text{if } 2 \leqslant x < 1 \\ 3 & \text{if } \ x = 1 \\ 2  3x^2/4 & \text{if } 1 \leqslant x < 2 \\ 3x^2/4 + 6x  10 & \text{if } \ 2 < x \leqslant 4\end{cases}$ 
September 19th, 2015, 06:39 AM  #3 
Math Team Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 
skipjack is assuming that the curved portions are parabolas. That cannot be determined from the graphs.

September 19th, 2015, 08:22 AM  #4 
Math Team Joined: Jul 2011 From: Texas Posts: 3,016 Thanks: 1600  

Tags 
find, graphs 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
graphs f(x)=1+e^(2x) and g(x)=10x+2, 0<=x<=1.5.  rhubarb123  PreCalculus  1  May 16th, 2014 08:23 AM 
Simply Magic Graphs  How many can you find?  FaustoMorales  Math Events  26  May 11th, 2013 12:07 PM 
two graphs at once at wa  ungeheuer  Math Software  2  February 4th, 2013 08:34 AM 
Question on isomorph Graphs and their complement Graphs  MageKnight  Applied Math  0  January 17th, 2013 10:38 PM 
How to find the area enclosed by the graphs  buckeyefan  Calculus  5  April 8th, 2011 02:37 PM 