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 February 24th, 2011, 04:59 PM #1 Newbie   Joined: Feb 2011 Posts: 21 Thanks: 0 Need Help! Linear approximation! The demand function for a product is given by p=f(q)=70? squareroot( q) where p is the price per unit in dollars for q units. Use the linear approximation to approximate the the price when 1224 units are demanded. Solution: We want to approximate f(1224) . From f(q)?L(q)=f(a)+f'(a)(q?a) and the fact that f'(a)= (choices are ( -1/sqrt(a) ,1/(2sqrt(a)), -1/(2sqrt(a)), 1/sqrt(a)) we choose a= From f(1225)= and f'(1225)= we get f(1224) . Hence, the price per unit when 1224 units are demanded is approximately \$ . February 24th, 2011, 05:25 PM #2 Senior Member   Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Need Help! Liner approximation! We may use the linear approximation to f(q) by the point-slope formula: With we have so and since and we choose a = 1225. Thus with: and we have: This is very close to the actual value of f(1224). February 24th, 2011, 05:43 PM #3 Newbie   Joined: Feb 2011 Posts: 21 Thanks: 0 Re: Need Help! Linear approximation! THANK YOU !!!! Tags approximation, linear Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post RGNIT Calculus 0 March 20th, 2014 11:21 PM 84grandmarquis Applied Math 2 October 20th, 2013 04:50 PM pomazebog Calculus 2 February 21st, 2012 11:52 PM shango Calculus 1 October 27th, 2009 02:45 PM dk1702 Abstract Algebra 1 December 31st, 1969 04:00 PM

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