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 Calculus Calculus Math Forum

 February 20th, 2011, 09:18 PM #1 Newbie   Joined: Feb 2011 Posts: 6 Thanks: 0 Derivatives: Linear Approximation The demand function for a product is given by p=f(q)=60??q where p is the price per unit in dollars for q units. Use the linear approximation to approximate the the price when 899 units are demanded. Solution: We want to approximate f(899). From f(q)? L(q)=f(a)+f'(a)(q?a) and the fact that f'(a)= either -1/sqrt(a) OR 1/(2sqrt(a)) OR -1/(2sqrt(a)) OR 1/sqrt(a) we choose a= _______. From f(900)= _____ and f'(900)= ______ we get f(899)? ________ . Hence, the price per unit when 899 units are demanded is approximately \$______ February 20th, 2011, 09:31 PM #2 Senior Member   Joined: Feb 2009 From: Adelaide, Australia Posts: 1,519 Thanks: 3 Re: Derivatives: Linear Approximation f(q)=60??q Do you know how to differentiate this? Write it as and have a go. Tags approximation, derivatives, linear Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post RGNIT Calculus 0 March 20th, 2014 11:21 PM ProJO Differential Equations 5 February 24th, 2011 06:28 PM Luckyy Calculus 2 February 24th, 2011 05:43 PM TsAmE Calculus 1 April 26th, 2010 03:33 PM shango Calculus 1 October 27th, 2009 02:45 PM

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