My Math Forum  

Go Back   My Math Forum > College Math Forum > Calculus

Calculus Calculus Math Forum

LinkBack Thread Tools Display Modes
February 20th, 2011, 09:18 PM   #1
Joined: Feb 2011

Posts: 6
Thanks: 0

Derivatives: Linear Approximation

The demand function for a product is given by

where p is the price per unit in dollars for q units. Use the linear approximation to approximate the the price when 899 units are demanded.

Solution: We want to approximate f(899). From
f(q)? L(q)=f(a)+f'(a)(q?a)
and the fact that f'(a)= either -1/sqrt(a) OR 1/(2sqrt(a)) OR -1/(2sqrt(a)) OR 1/sqrt(a)
we choose a= _______.

From f(900)= _____ and f'(900)= ______ we get f(899)? ________ .
Hence, the price per unit when 899 units are demanded is approximately $______
Oranges'n'Lemons is offline  
February 20th, 2011, 09:31 PM   #2
Senior Member
Joined: Feb 2009
From: Adelaide, Australia

Posts: 1,519
Thanks: 3

Re: Derivatives: Linear Approximation


Do you know how to differentiate this? Write it as and have a go.
aswoods is offline  

  My Math Forum > College Math Forum > Calculus

approximation, derivatives, linear

Thread Tools
Display Modes

Similar Threads
Thread Thread Starter Forum Replies Last Post
Linear approximation of Non linear system by Taylor series RGNIT Calculus 0 March 20th, 2014 11:21 PM
Derivatives: Differential and Linear approximation HELP ProJO Differential Equations 5 February 24th, 2011 06:28 PM
Need Help! Linear approximation! Luckyy Calculus 2 February 24th, 2011 05:43 PM
Derivatives/linear approximation problem TsAmE Calculus 1 April 26th, 2010 03:33 PM
Linear approximation shango Calculus 1 October 27th, 2009 02:45 PM

Copyright © 2019 My Math Forum. All rights reserved.