- **Calculus**
(*http://mymathforum.com/calculus/*)

- - **Derivatives: Linear Approximation**
(*http://mymathforum.com/calculus/17614-derivatives-linear-approximation.html*)

Derivatives: Linear ApproximationThe demand function for a product is given by p=f(q)=60??q where p is the price per unit in dollars for q units. Use the linear approximation to approximate the the price when 899 units are demanded. Solution: We want to approximate f(899). From f(q)? L(q)=f(a)+f'(a)(q?a) and the fact that f'(a)= either -1/sqrt(a) OR 1/(2sqrt(a)) OR -1/(2sqrt(a)) OR 1/sqrt(a) we choose a= _______. From f(900)= _____ and f'(900)= ______ we get f(899)? ________ . Hence, the price per unit when 899 units are demanded is approximately $______ |

Re: Derivatives: Linear Approximationf(q)=60??q Do you know how to differentiate this? Write it as and have a go. |

All times are GMT -8. The time now is 10:48 PM. |

Copyright © 2019 My Math Forum. All rights reserved.