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October 21st, 2010, 12:30 AM   #1
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Newton's Method

x^3=17x+34

= x^3 - 17x - 34 = 0

x^3 - 17x - 34 (that is f(x))

X0 = 6

Find X1 and |X1-X0|

So Xn+1 = Xn - f(Xn) / f'(Xn)

So Xn+1 = Xn - Xn^3 - 17Xn - 34 / 3Xn^2 - [color=#BF0000]17n[/color]?

How do I derive that 17Xn? I'm confused at that part basically, because I don't know what to do with 17n (if I did do that right).

Thanks.
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October 21st, 2010, 01:36 AM   #2
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Re: Newton's Method

You can just let that be 17. So you are working with:



The brackets aren't necessary, it's for your understanding.
Does the exercise require you to use Newton's method?

Hoempa
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October 21st, 2010, 01:46 AM   #3
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Re: Newton's Method

Quote:
Originally Posted by Hoempa
You can just let that be 17. So you are working with:



The brackets aren't necessary, it's for your understanding.
Does the exercise require you to use Newton's method?

Hoempa
Yeah we have to use Newton's method... I think that may be it, one minute
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October 21st, 2010, 01:50 AM   #4
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Re: Newton's Method

Yeah it is, thanks a lot!
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October 21st, 2010, 01:51 AM   #5
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Re: Newton's Method

You're welcome, good luck!
Can you go from here?

Hoempa
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