October 21st, 2010, 12:30 AM  #1 
Member Joined: Sep 2010 Posts: 55 Thanks: 0  Newton's Method
x^3=17x+34 = x^3  17x  34 = 0 x^3  17x  34 (that is f(x)) X0 = 6 Find X1 and X1X0 So Xn+1 = Xn  f(Xn) / f'(Xn) So Xn+1 = Xn  Xn^3  17Xn  34 / 3Xn^2  [color=#BF0000]17n[/color]? How do I derive that 17Xn? I'm confused at that part basically, because I don't know what to do with 17n (if I did do that right). Thanks. 
October 21st, 2010, 01:36 AM  #2 
Math Team Joined: Apr 2010 Posts: 2,780 Thanks: 361  Re: Newton's Method
You can just let that be 17. So you are working with: The brackets aren't necessary, it's for your understanding. Does the exercise require you to use Newton's method? Hoempa 
October 21st, 2010, 01:46 AM  #3  
Member Joined: Sep 2010 Posts: 55 Thanks: 0  Re: Newton's Method Quote:
 
October 21st, 2010, 01:50 AM  #4 
Member Joined: Sep 2010 Posts: 55 Thanks: 0  Re: Newton's Method
Yeah it is, thanks a lot!

October 21st, 2010, 01:51 AM  #5 
Math Team Joined: Apr 2010 Posts: 2,780 Thanks: 361  Re: Newton's Method
You're welcome, good luck! Can you go from here? Hoempa 

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