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 June 3rd, 2010, 09:11 AM #1 Member   Joined: Feb 2008 Posts: 30 Thanks: 0 Related Rates Problem: Find rate that distance is changing. A man walks north at 1.8m/s, a woman walks east at 2m/s. At what rate is the distance between them increasing after one minute if they leave from the same point at the same time. Attempt @ Work: dx/dt = 1.8m/s dy/dt = 2m/s Find dz/dt after 60 seconds. I made a triangle. 60 * 1.8 = 108m/s 60 * 2 = 120m/s Pythagorean Theorem 120^2 + 108^2 = z^2 z = ~161.44 x^2 + y^2 = z^2 Differentiate 2x * dx/dt + 2y * dy/dt = 2z * dz/dt Replace variables in [ 2(10 (1.8 )+2(120)(2) ] / [2(161.44)] = 2.7 June 3rd, 2010, 11:55 AM #2 Guest   Joined: Posts: n/a Thanks: Re: Related Rates Problem: Find rate that distance is changing. Yep. That's what I get. Good show Unless we're both wrong, but I don't think so.
 June 5th, 2010, 04:34 AM #3 Senior Member   Joined: Jan 2009 Posts: 344 Thanks: 3 Re: Related Rates Problem: Find rate that distance is changing. Nice work It would be nice to visualize all this on an x-y plane and it would be convenient to use dy/dt for the man moving north (along the y axis) and dx/dt for the woman moving east (along the x-axis) I'm just saying. Tags changing, distance, find, problem, rate, rates, related Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Shamieh Calculus 5 October 8th, 2013 06:58 PM Singularity Calculus 2 December 1st, 2012 07:56 PM fran1942 Calculus 3 April 30th, 2012 10:18 PM imcutenfresa Calculus 1 September 22nd, 2009 03:26 PM noselord Calculus 3 January 18th, 2008 03:57 AM

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