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 May 19th, 2010, 03:39 PM #1 Newbie   Joined: Mar 2010 Posts: 18 Thanks: 0 Maxima Calculate the maximum volume of a cuboid with a surface area of $10m^2$ Attempt: The volume is xyz The surface area is 2xy + 2yz + 2xz = 10 So I take the surface area as a constraint. Using Lagrange multiplier method, we get: $1= \lambda2y$ $1= \lambda2z$ $1= \lambda2x$ so we get x=y=z and then we get$6x^2= 10$ meaning $x, y, z=$ $+/- sqrt{5/3}$ am I right?
 May 19th, 2010, 04:52 PM #2 Senior Member   Joined: Apr 2008 Posts: 435 Thanks: 0 Re: Maxima This looks pretty solid to me.
 May 20th, 2010, 12:37 AM #3 Newbie   Joined: Mar 2010 Posts: 18 Thanks: 0 Re: Maxima Thank you!

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