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May 5th, 2010, 10:01 AM   #1
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Find the center, vertices, foci and eccentricity

Find the center, vertices, foci and eccentricity of the ellipse given by the following problem.
x^2 / 11 + y^2 / 36 =1. Did I do it right? Thanks
Center: (0,0)
Vertices: (0,6) and (0,-6)
Foci: (0,5) and (0, -5)
eccentricity= 5/6

a^2=36 a=6

b^2=11 b=square root of 11 = 3.32

a^2=b^2+c^2

36=11+c^2

25=C^2

c=5

e=c/a = 5/6
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May 5th, 2010, 02:27 PM   #2
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Re: Find the center, vertices, foci and eccentricity

It looks very good to me, although I don't know what the vertices of an ellipse are - so I couldn't really look into those.
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May 5th, 2010, 08:29 PM   #3
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Re: Find the center, vertices, foci and eccentricity

Quote:
Originally Posted by jason.spade
It looks very good to me, although I don't know what the vertices of an ellipse are - so I couldn't really look into those.
They are typically the endpoints of the major axis (i.e. the points on the major axis and on the curve).
"Covertices" are the analogous points on the minor axis.
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