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May 5th, 2010, 10:01 AM  #1 
Member Joined: Sep 2009 Posts: 43 Thanks: 0  Find the center, vertices, foci and eccentricity
Find the center, vertices, foci and eccentricity of the ellipse given by the following problem. x^2 / 11 + y^2 / 36 =1. Did I do it right? Thanks Center: (0,0) Vertices: (0,6) and (0,6) Foci: (0,5) and (0, 5) eccentricity= 5/6 a^2=36 a=6 b^2=11 b=square root of 11 = 3.32 a^2=b^2+c^2 36=11+c^2 25=C^2 c=5 e=c/a = 5/6 
May 5th, 2010, 02:27 PM  #2 
Senior Member Joined: Apr 2008 Posts: 435 Thanks: 0  Re: Find the center, vertices, foci and eccentricity
It looks very good to me, although I don't know what the vertices of an ellipse are  so I couldn't really look into those.

May 5th, 2010, 08:29 PM  #3  
Global Moderator Joined: Nov 2009 From: Northwest Arkansas Posts: 2,766 Thanks: 4  Re: Find the center, vertices, foci and eccentricity Quote:
"Covertices" are the analogous points on the minor axis.  

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