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April 6th, 2010, 06:54 PM   #1
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integration

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April 6th, 2010, 07:03 PM   #2
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I think this integral can't be done in terms of the usual elementary functions.
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April 7th, 2010, 02:36 PM   #3
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Re: integration

sorry I edited a couple times would it be ((x-x^3)^4/3)/4/3
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April 7th, 2010, 06:26 PM   #4
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Re: integration

Quote:
Originally Posted by nycmets718
sorry I edited a couple times would it be ((x-x^3)^4/3)/4/3
No it wouldn't. The problem is the x - x^3. I can't think of any way to integrate that for now, unless you want to use integration by parts somehow, but that doesn't seem right.

Edit: Don't know if this helps, but you can also say (x(1-x)(1+x))^1/3

But thinking a little more on it, you could also say (x(1-x^2))^1/3

let u = 1-x^2
du = -2x dx

so...-2[(u)^1/3 du](of course don't forget the integral)
then I think you can go from there
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April 8th, 2010, 02:54 PM   #5
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Re: integration

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April 8th, 2010, 06:57 PM   #6
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Re: integration

Yeah, I knew I was wrong from the beginning. That's a lot of work for a small problem.
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April 10th, 2010, 07:59 AM   #7
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Well done, rose. Your image is a bit difficult to read, but looks okay, except that the final answer isn't defined for x = 0. However, some simple manipulation can be used to convert it to a form that is defined for x = 0 (and equivalent elsewhere).
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April 11th, 2010, 08:59 AM   #8
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Re: integration

good thinking
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October 25th, 2017, 01:08 AM   #9
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That is basic integration.

Hint- Check the integration formulas here.
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