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SOLUTIONS
finds favour in the nursery. The general solution is that for
n
men
the number must be
m(n
n+1
) -
(n - 1), where
m
is any integer.
Each man will receive
m(n-
1 )
n
- 1 biscuits at the final division,
though in the case of two men, when
m
= 1, the final distribution
only benefits the dog. Of course, in every case each man steals an
nth of the number of biscuits, after giving the odd one to the dog.
THE END



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