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 November 23rd, 2009, 12:54 PM #1 Newbie   Joined: Nov 2009 Posts: 5 Thanks: 0 Please help with Gamma function. Can you show me how to get the series representation of Gamma(n-3/2+1)? For example Gamma[(n+3/2+1)=(2n+3)(2n+1)!]/{[2^(2n+2)] n!} I cannot figure out how to write a series with: n=0 => Gamma(0-3/2+1)= -2 sqrt(pi) n=1 => Gamma(1-3/2+1)= sqrt(pi) n=2 => Gamma(2-3/2+1)= 1/2 sqrt(pi) n=3 => Gamma(3-3/2+1)= 4/3 sqrt(pi) Also, I am new here, can you tell me how can I post with math symbols. I just cannot get a series representation for this gamma function for n=0,1,2....... I have no problem getting the representation for n=1,2,3...... It is the n=0 that gets me!!!! Thanks Alan

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