
Applied Math Applied Math Forum 
 LinkBack  Thread Tools  Display Modes 
August 25th, 2009, 12:44 AM  #1 
Newbie Joined: Aug 2009 Posts: 1 Thanks: 0  Permutation with variables & numbers
Hi. Not sure if this belongs here... I'm trying to find the number of different combinations with, say, 3 different groups. [AZ(22)] [09(10)] and [09(10)] I attempted to set up some type of factorial of this (didn't think the pascal triangle would help), but alas I'm too baked to actually write out the thousands of possible combinations (which explains why I'm on a math forum while I'm out of school asking about middle school caliber math) there would be 6 different combinations w/ 1 letter ,n1, and n2 (a12 a21 1a2 12a 2a1 21a) then theres the number of different combinations of numbers 10 ! 10 ! 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 _______ =_______=______________________________ = 10 x 9 = 90 (10  2) ! 8 ! 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 so w/ 90 different combinations of numbers to choose , 22 letters, and 6 possible places each can hold, would you just subtract 1 set for each multiplicity? n1 n2 have 12 places for each letter amidoinitrite? Thanks in advance. 
August 25th, 2009, 05:29 AM  #2 
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms  Re: Permutation with variables & numbers
I don't understand what combinations you're allowing. You can choose from 22 (or 26?) letters, but can each slot hold a letter? Can they be repeated? Does order matter? what does "6 possible places each can hold" mean? Maybe an example would help.


Tags 
numbers, permutation, variables 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
permutation help please  righteous818  Algebra  3  March 20th, 2013 09:10 AM 
Permutation  abramo_k  Algebra  4  February 27th, 2013 12:11 PM 
PERMUTATION  toli  Number Theory  15  March 12th, 2012 05:03 AM 
Permutation  daemonlies  Algebra  3  April 29th, 2011 03:38 PM 
permutation help please  righteous818  Advanced Statistics  0  December 31st, 1969 04:00 PM 