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 September 18th, 2014, 04:19 AM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,664 Thanks: 2643 Math Focus: Mainly analysis and algebra Suppose we have a solution that is $\frac{a}{100}$ths ($a%$) resin and we want to make the solution $\frac{b}{100}$ resin. Further, suppose that we have $V$mL of solution. Our inital solution contains $\frac{aV}{100}$mL of resin and the rest is water. We want to replace $S$mL of solution with resin, so that the final amount of resin is $\frac{bV}{100}$mL. Thus we remove $\frac{aS}{100}$ of resin and add $S$mL. We therefore want \begin{align*}\frac{aV}{100} - \frac{aS}{100} + S &= \frac{bV}{100} \\ S(100-a) &= V(b-a) \\[12pt] \implies S &= V \frac{b-a}{100-a} \end{align*} Thanks from LisaBio
 September 18th, 2014, 05:27 AM #3 Newbie   Joined: Sep 2014 From: Wageningen Posts: 2 Thanks: 0 Well... I tried something and I think I did get quite close to that (but quite close is never really right, right?). This makes more sense. Thank you for your answer Have a nice day!

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