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March 5th, 2013, 12:07 PM   #1
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Holder's spces

Hello,
I want to know, with any norm we can provide with and bounded ,open domain in .

thank's
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March 5th, 2013, 01:41 PM   #2
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Re: Holder's spces

no one, .
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March 5th, 2013, 02:13 PM   #3
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Re: Holder's spces

You might get a response if you define your notation.
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March 6th, 2013, 01:50 AM   #4
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Re: Holder's spces

Thank you,

We say a function in if and only if is from the first variable, from the second variable.

But, How I can define an norm? !
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March 6th, 2013, 01:28 PM   #5
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Re: Holder's spces

Quote:
Originally Posted by x-member
Thank you,

We say a function in if and only if is from the first variable, from the second variable.

But, How I can define an norm? !




All of the above use notation I have never seen before, especially
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March 6th, 2013, 01:48 PM   #6
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Re: Holder's spces

means the function with this amount is finished.
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March 7th, 2013, 01:24 PM   #7
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Re: Holder's spces

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Originally Posted by x-member
means the function with this amount is finished.
, what is D? Are both D terms divided?

finished ?
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