August 8th, 2017, 04:42 AM  #1  
Senior Member Joined: Feb 2016 From: Australia Posts: 1,453 Thanks: 489 Math Focus: Yet to find out.  Convex function Quote:
 
August 9th, 2017, 11:02 PM  #2 
Senior Member Joined: Feb 2016 From: Australia Posts: 1,453 Thanks: 489 Math Focus: Yet to find out.  
August 16th, 2017, 06:52 AM  #3 
Math Team Joined: Jan 2015 From: Alabama Posts: 2,872 Thanks: 766 
When $\displaystyle \lambda$ is 0, $\displaystyle \lambda x+ (1 \lambda)y= (0)x+ (1)y$ is just y. When $\displaystyle \lambda$ is 1, $\displaystyle \lambda x+ (1 \lambda)y= (1)x+ (0)y$ is just x. Since that is a linear formula, as $\displaystyle \lambda$ goes from 0 to 1, the point moves on the straight line from y to x.
Last edited by greg1313; August 16th, 2017 at 08:02 AM. 
August 16th, 2017, 04:40 PM  #4  
Senior Member Joined: Feb 2016 From: Australia Posts: 1,453 Thanks: 489 Math Focus: Yet to find out.  Quote:
 

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