My Math Forum Calculating weight lifted/force required to move an object

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 February 15th, 2013, 01:17 PM #1 Newbie   Joined: Feb 2013 Posts: 1 Thanks: 0 Calculating weight lifted/force required to move an object I apologise in advance if this is not the right section of the forum to place this, not being that adept at math means I may not have understood all of the types of math, but I put this in the one that looked ok to me. So my question is the following; If someone or a machine lifts up an object, but not fully off the ground, lets say they only lifted a corner. Lets use a 1 meter cubed box or steel crate. How do I calculate, how much force/weight they actually lifted. If I am not mistaken, using the opposite corner/edge of say a box to flip something over would mean your not necesserily moving the whole weight, because some of it is still on the ground, is this true? How would one calculate how much force or weight someone or something lifted from this one edge, if they did not lift it fully off the ground, all edges in the air? Thank you for any information on the subject.
 February 21st, 2013, 02:39 PM #2 Newbie   Joined: Feb 2013 Posts: 2 Thanks: 0 Re: Calculating weight lifted/force required to move an obje Take this as a response from the layman. You calculate the change in the potential energy of the extreme states- that is how much work you have done. And then it is a question of how fast you want things to happen. That is because an applied force on a mass is exerted by acceleration of the object. If you want precise information on how much force you need to apply in order to lift it at a constant speed holding one corner, you need to define the direction of the force etc. For example, rotating a box around the opposite-corners axis requires more energy obviously because the particles of the box get higher on average. It is easy to see that because of the symmetry. The difference the average height times mG gives you the potential energy required. (E=mgh) Hope it helps.

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