January 31st, 2017, 02:22 PM  #1 
Newbie Joined: Jan 2017 From: West Olive, MI Posts: 1 Thanks: 0  Production Rates
Hello, I've been working on this for days and can't seem to figure it out. I'm not sure if this is the right place to post this, so I apologize if it isn't. I'm trying to figure out maximum production rates (parts per hour) per person running multiple machines. The number of machines that can be run should be determined by the disposable time left over after each machine. Some sample data: Machine 1: Load Time: 20 seconds Cycle Time (machine running): 450 seconds Added Value (while machine running): 10 seconds Machine 2: Load Time: 80 seconds Cycle Time (machine running): 100 seconds Added Value (while machine running): 10 seconds Machine 3: Load Time: 10 seconds Cycle Time (machine running): 90 seconds Added Value (while machine running): 10 seconds Machine 4: Load Time: 30 seconds Cycle Time (machine running): 90 seconds Added Value (while machine running): 20 seconds I'm trying to come up with a way to determine maximum number of parts per hour for each machine assuming that the person can only be at one machine at a time. Thanks in advance for any help! 
February 8th, 2017, 02:50 AM  #2 
Senior Member Joined: Apr 2014 From: Glasgow Posts: 1,988 Thanks: 646 Math Focus: Physics, mathematical modelling, numerical and computational solutions 
This looks like a typical work balancing (linearoptimization) problem , but I just need some clarification: 1. What do you mean by "Added value (while machine running)"? 2. Does a person need to babysit each machine whilst it is running or can they go and load another machine once it is running? 3. Does each machine produce one part? 4. Does each machine produce the same part or do they make different parts? 5. Does each machine need parts from other machines to run (i.e. are the machines dependent on each other)? You might be able to get a good idea of the performance of each machine by calculating the number of parts produced per second for each machine and then just use the best one, but that might be oversimplifying the problem. 

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