October 4th, 2012, 06:14 PM  #1 
Member Joined: Sep 2012 Posts: 69 Thanks: 0  Combinatoric!!!
[attachment=0:klq5pgoz]Capture.PNG[/attachment:klq5pgoz] How would u solve c through f?? I got how to do a ,b but no idea on c  f!! This is problem using combination with repetition. 
October 5th, 2012, 12:24 AM  #2 
Senior Member Joined: Aug 2012 Posts: 229 Thanks: 3  Re: Combinatoric!!!
Hey eChung00. Can you use a computer? For this problem, a computer will give an answer really quickly. 
October 5th, 2012, 01:04 AM  #3 
Newbie Joined: Oct 2012 Posts: 1 Thanks: 0  Re: Combinatoric!!!
For (C) Assume  X1 = K1+5 and X2 = K2+5 where K1,K2 >= 0, similarly X3 = K3+7, X4 = K4 +7; K3,K4 >=0. Now the initial equation can be rewritten as (K1+5)+(K2+5)+(K3+7)+(K4+7)=32 which implies K1+K2+K3+K4 = 8 and all K >=0  This is the Problem mentioned in (A). The number of integer solutions would be = (8+41) C (4) = Factorial (11) / (Factorial(114) x Factorial 4) = 330. Same is the logic for rest of the things as well... Cheers 

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