My Math Forum Combinatoric!!!

 Applied Math Applied Math Forum

October 4th, 2012, 06:14 PM   #1
Member

Joined: Sep 2012

Posts: 69
Thanks: 0

Combinatoric!!!

[attachment=0:klq5pgoz]Capture.PNG[/attachment:klq5pgoz]

How would u solve c through f?? I got how to do a ,b but no idea on c - f!!
This is problem using combination with repetition.
Attached Images
 Capture.PNG (13.0 KB, 135 views)

 October 5th, 2012, 12:24 AM #2 Senior Member   Joined: Aug 2012 Posts: 229 Thanks: 3 Re: Combinatoric!!! Hey eChung00. Can you use a computer? For this problem, a computer will give an answer really quickly.
 October 5th, 2012, 01:04 AM #3 Newbie   Joined: Oct 2012 Posts: 1 Thanks: 0 Re: Combinatoric!!! For (C) Assume - X1 = K1+5 and X2 = K2+5 where K1,K2 >= 0, similarly X3 = K3+7, X4 = K4 +7; K3,K4 >=0. Now the initial equation can be re-written as (K1+5)+(K2+5)+(K3+7)+(K4+7)=32 which implies K1+K2+K3+K4 = 8 and all K >=0 ----- This is the Problem mentioned in (A). The number of integer solutions would be = (8+4-1) C (4) = Factorial (11) / (Factorial(11-4) x Factorial 4) = 330. Same is the logic for rest of the things as well... Cheers

 Tags combinatoric

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post eChung00 Applied Math 2 October 7th, 2012 05:29 AM eChung00 Applied Math 0 October 4th, 2012 05:28 PM eChung00 Applied Math 1 September 17th, 2012 04:25 PM wulfgarpro Algebra 2 June 1st, 2010 12:49 AM junho Applied Math 0 February 14th, 2008 05:12 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top