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December 13th, 2015, 05:37 AM   #1
Has
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Graph theory: Prove that each cycle has minimum length of 5

How do I prove that each cycle in this graph has a minimum length of 5?


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December 29th, 2015, 11:58 AM   #2
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Hi,
I think it suffices to prove it for selected fixed vertex v0 - because the graph is symmetric (automorphism is eg. every mapping sending vertex v to vertex not adjacent with v). And checking it for v0 is easy - it can be seen that cycle of length 3 and 4 doesn't exist.
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March 22nd, 2016, 09:33 AM   #3
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How do I prove that every circulant of girth at least 4 and with degree 4 is non-planar?
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