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 uterfor86 February 12th, 2012 01:17 PM

compute eigenvalue

hi,

$\ dy/dx=y(y-1)(y-2)\$

I think I got the equilibrium steady states right: y =0, y=1, y=2

Not sure how to use those in order to find the eigenvalues. I know that the formula to find the eigenvalue is $\ Av=\lambda v\$

Any help will be greatly appreciated. Thks

 wnvl February 12th, 2012 02:58 PM

Re: compute eigenvalue

To what does A correspond in this differential equation?

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