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October 12th, 2011, 02:46 PM   #1
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Empty Set proof

Hey everyone, was wondering if someone could offer help on the following proof about set theory:

The empty set is a subset of every set, that is, for every set S, ? S.

Not sure how to tackle this....
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October 12th, 2011, 05:40 PM   #2
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Re: Empty Set proof

Moved to Set Theory.

The proof itself is trivial; the difficulty is formulating it properly for your class. (If a set is the things you have in your pocket and a subset is the things you can pull out of your pocket, regardless of what's in your pocket you can always pull your hand out empty.)

To do that, we'll need to know how your class defines "subset".
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