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March 24th, 2011, 04:47 PM   #1
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absorption laws:

I thought that

(A?B')?B=A?B.

is proven by the above law however that seems too simple. Is that completely wrong or is there another way.

thankyou
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March 24th, 2011, 09:33 PM   #2
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Re: absorption laws:

It isn't quite the absorption law, because B' is inside the parentheses, while the quantity outside the parentheses is B. However, it is certainly true that \cup(A\cap B)=A" />, and that . From this, we can conclude that \cup B\supseteq A\cap B'\cup(A\cap B)=A" /> and then we can take the union of each side with B to derive \cup B\supseteq A\cup B" />. But we also have \cup B\subseteq A\cup B" /> trivially, and therefore \cup B=A\cup B" />.
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March 25th, 2011, 01:03 AM   #3
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Re: absorption laws:

Thats brilliant, I get it. Thanks very much.
Im trying to stay within the laws as well. Are these specific to each law?
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