My Math Forum absorption laws:

 Applied Math Applied Math Forum

 March 24th, 2011, 03:47 PM #1 Newbie   Joined: Mar 2011 Posts: 2 Thanks: 0 absorption laws: I thought that (A?B')?B=A?B. is proven by the above law however that seems too simple. Is that completely wrong or is there another way. thankyou
 March 24th, 2011, 08:33 PM #2 Senior Member   Joined: Nov 2006 From: I'm a figment of my own imagination :? Posts: 848 Thanks: 0 Re: absorption laws: It isn't quite the absorption law, because B' is inside the parentheses, while the quantity outside the parentheses is B. However, it is certainly true that $(A\cap B'\cup(A\cap B)=A" />, and that $(A\cap B)\subseteq B$. From this, we can conclude that $(A\cap B'\cup B\supseteq A\cap B'\cup(A\cap B)=A" /> and then we can take the union of each side with B to derive $(A\cap B'\cup B\supseteq A\cup B" />. But we also have $(A\cap B'\cup B\subseteq A\cup B" /> trivially, and therefore $(A\cap B'\cup B=A\cup B" />.
 March 25th, 2011, 12:03 AM #3 Newbie   Joined: Mar 2011 Posts: 2 Thanks: 0 Re: absorption laws: Thats brilliant, I get it. Thanks very much. Im trying to stay within the laws as well. Are these specific to each law?

 Tags absorption, laws

### absorption law by induction maths

Click on a term to search for related topics.
 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post rhymin Algebra 3 March 25th, 2013 03:28 AM macca1994 Advanced Statistics 0 February 4th, 2013 02:18 PM FloorPlay Applied Math 2 December 4th, 2012 12:11 PM happysmiles374 Elementary Math 2 February 28th, 2012 08:48 AM Alex510 Calculus 1 October 6th, 2008 07:21 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top