My Math Forum problems in Gama function;i am very shy!!!!!

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 December 24th, 2010, 02:22 AM #1 Newbie   Joined: Dec 2010 Posts: 11 Thanks: 0 problems in Gama function;i am very shy!!!!! [color=#FF0040]I am very happy that I found the answer to my first question, so I am more happy that Mr ZardoZ began with me. I do not forget the beginning!!!! My problem is: prove that $\Gamma \left( {-m + 1/2} \right)= \frac{{\mathop {\left( { - 1} \right)}\nolimits^m \mathop 2\nolimits^m \sqrt \pi }}{{1.3.5.....\left( {2m - 1} \right)}}$ using $\Gamma \left( {1 + x} \right)= x\Gamma \left( x \right)$ please if you solve it soon it is very good. I try to solve it but i cannot.[/color] [color=#8000FF]Note: the bracket [/mathop?] you can neglet[/color]
 December 24th, 2010, 02:17 PM #2 Global Moderator   Joined: May 2007 Posts: 6,416 Thanks: 558 Re: problems in Gama function The question is confusing. You seem to be asking to prove something (first equation) by assuming something (second equation), but the equations look identical.
 December 24th, 2010, 06:56 PM #3 Math Team   Joined: Nov 2010 From: Greece, Thessaloniki Posts: 1,989 Thanks: 133 Math Focus: pre pre pre pre pre pre pre pre pre pre pre pre calculus Re: problems in Gama function [color=#000000]Also I think that what you are asking is wrong. This equation holds for ?(1/2-m).[/color]
 December 24th, 2010, 08:08 PM #4 Senior Member   Joined: Nov 2010 Posts: 502 Thanks: 0 Re: problems in Gama function Are you misspelling things on purpose? I feel like I'm being trolled or something. Further, unless mathop means something different for each equation, you have the same thing written twice.
 December 25th, 2010, 02:42 AM #5 Newbie   Joined: Dec 2010 Posts: 11 Thanks: 0 Re: problems in Gama function;i have corrected the question Hello Mr [color=#FF0040]mathman[/color] ,Mr [color=#FF00FF]ZardoZ[/color] and Mr[color=#FF8000] DLowry [/color]. [color=#4000FF]Thank you for helping please accept my apology the mistake {is} out of my control.Now i have corrected the question [/color]$\Gamma \left( {1 + x} \right)= x\Gamma \left( x \right)$ [color=#4000FF]you can see again the question. again I am very sorry[/color]
 December 25th, 2010, 02:31 PM #6 Global Moderator   Joined: May 2007 Posts: 6,416 Thanks: 558 Re: problems in Gama function;i correct the question You need a starting point. ?(1/2)=??. The rest follows from the recursion formula.
December 26th, 2010, 02:58 AM   #7
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Re: problems in Gama function

Quote:
 Originally Posted by ZardoZ [color=#000000]Also I think that what you are asking is wrong. This equation holds for ?(1/2-m).[/color]
[color=#FF0000]you are right[/color]

 December 26th, 2010, 03:17 AM #8 Newbie   Joined: Dec 2010 Posts: 11 Thanks: 0 Re: problems in Gama function;i am very shy!!!!! [color=#FF0000] I am very shy that i have mistake agian but it is the last mistake i am sure :i have found this equestion in many books but unfortunatly it is not proving[/color]

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